The average distance of the sun from earth is 390 times the average distance of the moon from earth. now consider a total eclipse of the sun (moon directly between earth and sun) and calculate (a) the ratio of the sun's diameter to the moon's diameter, and (b) the ration of the sun's volume to the moon's volume. (c) the angle intercepted at the eye by the moon is 0.52 degrees and the distance between earth and moon is 3.82 *10^5 km. calculate the diameter of the moon.

this is the answer , p = 1 + (1/10)x

step-by-step explanation:

we have,

at sea level pressure is 1 atmosphere (i.e at x =0, p0=1 atmosphere)

at depth 23 meters , pressure = 3.3 atmosphere

since the pressure increases at constant rate as the depth increases, so we can write a relation as:

p =p0 +   kx   , where p is the pressure  , p0 is the initial pressure, x is the depth and k is constant rate of increasing.

to find constant rate k, plug p = 3.3 , p0 = 1 and x= 23 meters

we get,

  3.3 = 1 + k * 23

k = 2.3 / 23   = 1/10

so we can write the function formula as:   p = 1 + (1/10)x

i would think its c but i'm not sure