I’m at situations can one generation learn from another

in the problem you wrote said that the taxi charges $0.070 per mile(which would be 7 cents per mile), but then in your suggested equation you have it as $0.70 per mile (which is 70 cents per mile).

the latter seems more realistic, so i will assume that the taxi costs $5.00 and charges $0.70 per mile with tolls costing an additional $3.50. and it asks you to find how far you can travel on $36.50.

let x the number of miles traveled. since the taxi charges $0.70 per mile, multiplying this by the miles traveled (x) will yield the cost of the taxi ride as far as how far it took you. then adding this amount to the cost of the taxi ($5.00) and the additional cost for the tolls ($3.50) will give you the total cost of the taxi ride ($36.50)

that is,

            (0.70)x + 5.00 + 3.50 = 36.50

adding the like terms on the left-hand side of this equation, we arrive at the following:

            (0.70)x + 8.50 = 36.50

subtracting 8.50 from both sides of the equation, we get:

            (0.70)x = 28.00

to solve for x, divide both sides of the equation above by the coefficient of x (that being, 0.70):

            x = 40

thus, you can travel up to 40 miles on $36.50

this is the answer , p = 1 + (1/10)x

step-by-step explanation:

we have,

at sea level pressure is 1 atmosphere (i.e at x =0, p0=1 atmosphere)

at depth 23 meters , pressure = 3.3 atmosphere

since the pressure increases at constant rate as the depth increases, so we can write a relation as:

p =p0 +   kx   , where p is the pressure  , p0 is the initial pressure, x is the depth and k is constant rate of increasing.

to find constant rate k, plug p = 3.3 , p0 = 1 and x= 23 meters

we get,

  3.3 = 1 + k * 23

k = 2.3 / 23   = 1/10

so we can write the function formula as:   p = 1 + (1/10)x