Draw the alkene formed when 1-heptyne is treated with one equivalent of hbr.

1-heptyne is a compound which consists of 7 carbons with a triple bond between the first and second C. When this reacts with HX (X being a halogen), it follows the Markovnikov Rule. This means that the hydrogen bonds with the carbon containing a lot of bonding hydrogen atoms. At the same time, the halogen bonds with the carbon with the least H atoms.

Thus, the product would be

2-bromo-1-heptene

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