If a variable X is normally distributed with a standard deviation of 8, what is the mean value of X, if 0.3413 of the values of X is greater than 58?

55

Explanation:

The z score is a score used in statistics to determine how many standard deviations the raw score is above or below the mean.it is given by the formula:

Given that:  

σ = 8, P(z > 58) = 0.3413, x > 58/ Hence:

P(z < 58) = 1 - P(z > 58) =  1 - 0.3413 = 0.6587

P(z < 58) = 0.6587

From the normal distribution table, P(z < 58) = 0.6587 corresponds with a z score of 0.41

μ ≅ 55

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