How many nickels and dimes are in $1.75 if there are three times more dimes than nickels?

a) 5 dimes and 15 nickels

b) 10 dimes and 30 nickels

c) 6 dimes and 18 nickels

d) 15 dimes and 5 nickels

Option D

There are 15 dimes and 5 nickels

Solution:

Let "d" be the number of dimes

Let "n" be the number of nickels

We know that,

Value of 1 dime = $ 0.10

Value of 1 nickel = $ 0.05

There are three times more dimes than nickels

Therefore,

Number of dimes = 3(number of nickels)

d = 3n ---------- eqn 1

The total value is $ 1.75

Therefore, we frame a equation as:

Number of dimes x Value of 1 dime + number of nickels x Value of 1 nickel = 1.75

0.10d + 0.05n = 1.75 -------- eqn 2

Substitute eqn 1 in eqn 2

0.10(3n) + 0.05n = 1.75

0.3n + 0.05n = 1.75

0.35n = 1.75

Substitute n = 5 in eqn 1

d = 5(3)

Thus there are 15 dimes and 5 nickels

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