A metre rule is supported at its middle point O. The block of weight 10N is suspended at point B,40 cm from O. find the weight of the block that balances it at point A,25 cm from O. I got 16N is it correct?
The way i did was 10N×40cm=400Nm
400Nm÷25cm= 16N​

The drive force for diffusion is 7 fick's first law can be used to solve the non-steady state diffusion. a)-true b)-false

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