Using OOP, write a C++ program that will read in a file of names. The file is called Names. txt and should be located in the current directory of your program. Read in and store the names into an array of 30 names. Sort the array using the selection sort or the bubblesort code found in your textbook. List the roster of students in ascending alphabetical order. Projects using global variables or all code is in main() will result in a grade submission of 0. List of names in Names. txt: Jackie Sam Bill Tom Mary Paul Zev Barb John Sharon Dana Dominic Steven Padro Katey Kathy Darius Angela Mimi Jesse Kenny Lynn Hector Brittany Jenn Joe Chloe Geena Sylvia Dean

This doesn't work fully, but it's a start. Good Luck

#include <iostream>

#include <fstream>

#include <string>

#include <cstdlib>

using namespace std;

class People

{

private:

const static int SIZE = 30;  

string names[SIZE];  

int birth_years[SIZE];  

int count;  

void sort();  

void display();  

public:

People();

void simulate();

};

People::People()

{

count = 0;

// open both files

ifstream namesFile, birthyearsFile;

namesFile.open("Names.txt");

birthyearsFile.open("BirthYear.txt");

while (!namesFile.eof() && !birthyearsFile.eof() && count < SIZE)

{

 getline(namesFile, names[count]);  

 birthyearsFile >> birth_years[count];  

 count++;  

}

// files open failed, exit the program

if (namesFile.fail() || birthyearsFile.fail())

{

 cout << "Unable to open input file(s). Terminating" << endl;

 exit(1);

}

//close the files

namesFile.close();

birthyearsFile.close();

sort();

display();

}

void People::sort()

{

for (int i = 0; i < count - 1; i++)

{

 for (int j = 0; j < count - 1 - i; j++)

 {

 if (names[j] > names[j + 1])

 {

   string tempName = names[j];

   names[j] = names[j + 1];

   names[j + 1] = tempName;

   int tempYear = birth_years[j];

   birth_years[j] = birth_years[j + 1];

   birth_years[j + 1] = tempYear;

 }

 }

}

}

void People::display()

{

cout << "Alphabetical Roster of Names: " << endl;

for (int i = 0; i < count; i++)

{

 cout << names[i] << "\t" << birth_years[i] << endl;

}

cout << endl;

}

void People::simulate()

{

int year;

cout << endl << "Names by Birth Year" << endl;

// input the birth year

cout << "Please enter the birth year: ";

cin >> year;

// loop that continues until valid input has been read

while (cin.fail() || year < 1995 || year > 2005)

{

 cin.clear();  

 cin.ignore(100, '\n');  

 cout << "Invalid birth year entered, try again: ";  

 cin >> year;

}

bool found = false;  

for (int i = 0; i < count; i++)

{

 if (birth_years[i] == year)  

 {

 if (!found)  

 {

   cout << endl << "For the birth year of " << year << ":" << endl;

   found = true;

 }

 // display the name

 cout << names[i] << endl;

 }

}

// no name with birth year found

if (!found)

 cout << endl << "No names with the birth year " << year << "." << endl;

cout << "End of results" << endl;

}

int main()

{

People people;  

people.simulate();  

return 0;

}

Explanation:

d would be the most obvious choice to this question. leaders are supposed to herd their underlings like a shepherd to sheep. a leader should also listen to others when they are talking to one other to gain a better understanding of their mission and surroundings.

explanation:

answer:

you cant but you can report the sender

and do you want to talk?

im xavier btw but i go by x

explanation: