he crimping tool is used to crimp the end of the wire E. If a force of 25.6 lb is applied to the handles, determine the average shear stress (in ksi) in the pin at B. The pin is subjected to single shear and has a diameter of 0.28 in. Only vertical force is exerted on the wire. Note: You answer should include requested units and be to 3 decimal places.

Shear Stress = 0.415 ksi

Explanation:

In order to find the shear stress we first need to find the cross sectional area of pin B. The area is given as follows:

A = πd²/4

where,

A = Area of cross section of pin = ?

d = diameter of pin = 0.28 in

Therefore,

A = π(0.28 in)²/4

A = 0.0615 in²

Now, the shear stress is given as:

Shear Stress = Shear Force/Area

Shear Stress = 25.6 lb/0.0615 in²

Shear Stress = 415.8 psi

Shear Stress = 0.415 ksi

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answer:

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