subject
Engineering, 15.10.2020 14:01 erin2077

A method for determining the thermal conductivity k and the specific heat cp of a material is illustrated in the sketch. Initially the two identical samples of diameter D= 60 mm and thickness L= 10 mm and the thin heater are at a uniform temperature of Ti= 23.00°C, while surrounded by an insulating powder. Suddenly the heater is energized to provide a uniform heat flux qo" on each of the sample interfaces, and the heat flux is maintained constant for a period of time, Δto. A short time after sudden heating is initiated, the temperature at this interface To is related to the heat flux as To(t)-Ti=2qo"(tπrhocpk)1/2. For a particular test run, the electrical heater dissipates 13.5 W for a period of Δto= 120 s, and the temperature at the interface is To(30 s)= 24.57 °C after 30 s of heating. A long time after the heater is deenergized, t≫Δ to, the samples reach the uniform temperature of [infinity] To([infinity])= 33.50 °C. The density of the sample materials determined by measurement of volume and mass, is rho= 6991 kg/m3. Required:
Determine the specific heat and thermal conductivity of the test material.

ansver
Answers: 3

Other questions on the subject: Engineering

image
Engineering, 03.07.2019 15:10, EmilySerna
Heat is added to a piston-cylinder device filled with 2 kg of air to raise its temperature 400 c from an initial temperature of t1 27 cand pressure of pi 1 mpa. the process is isobaric process. find a)-the final pressure p2 b)-the heat transfer to the air.
Answers: 1
image
Engineering, 04.07.2019 18:10, tjeffers90028
Refrigerant 134a enters an insulated compressor operating at steady state as saturated vapor at -26°c with a volumetric flow rate of 0.18 m3/s. refrigerant exits at 9 bar, 70°c. changes in kinetic and potential energy from inlet to exit can be ignored. determine the volumetric flow rate at the exit, in m3/s, and the compressor power, in kw.
Answers: 1
image
Engineering, 04.07.2019 18:10, 19deleonl
Coiled springs ought to be very strong and stiff. si3n4 is a strong, stiff material. would you select this material for a spring? explain.
Answers: 2
image
Engineering, 04.07.2019 18:10, xboxdude06
Slip occurs via two partial dislocations because of (a) the shorter path of the partial dislocation lines; (b) the lower energy state through partial dislocations; (c) the charge balance.
Answers: 1
You know the right answer?
A method for determining the thermal conductivity k and the specific heat cp of a material is illust...

Questions in other subjects:

Konu
Mathematics, 11.11.2019 13:31