In a production turning operation, an engineer wants a single pass must be completed on the cylindrical workpiece in 5.0 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.30 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement? Also calculate the material removal rate for this operation in cubic mm/seconds.

the  cutting speed that must be used to meet this machining time requirement is 125.66 m/min

the material removal rate for this operation is

Explanation:

Given that:

Time = 5mins

Length of the cylindrical workpiece = 400 mm  = 0.4 m

Diameter of the cylindrical workpiece = 150 mm = 0.15 m

Feed value = 0.30 mm/rev = m/rev

Depth of cut = 4.0

what cutting speed must be used to meet this machining time requirement?

The cutting speed can be estimated by using the formula:

where;

= time

Diameter

L = length

v = cutting speed

F = Feed value

Making v the subject; we have:

v = 125.66 m/min

Hence; the  cutting speed that must be used to meet this machining time requirement is 125.66 m/min

Also calculate the material removal rate for this operation in cubic mm/seconds.

The material removal rate for this operation is :

where ;

v  =  125.66 m/min

to mm/sec : we have.

= ((125.66 × 1000 )/60 ) mm/sec

= (125660/60) mm/sec

= 2094.33 mm/sec

F = 0.30 mm/rev

d = depth of the cut = 4.0 mm

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