For some transformation having kinetics that obey the Avrami equation , the parameter n is known to have a value of 1.1. If, after 114 s, the reaction is 50% complete, how long (total time) will it take the transformation to go to 87% completion y = 1 - exp(-kt^n)

total time  = 304.21 s

Explanation:

given data

y = 50% = 0.5

n = 1.1

t = 114 s

y = 1 - exp(-kt^n)

solution

first we get here k value by given equation

y = 1 -   ...........1    

put here value and we get

0.5 = 1 - e^{(-k(114)^{1.1})}    

solve it we get

k = 0.003786  = 37.86 ×

so here

y = 1 -

1 - y  =  

take ln both side

ln(1-y) = -k ×  

so

t =    .............2

now we will put the value of y = 87% in equation  with k and find out t

t =

total time  = 304.21 s

explanation:

which ordered pair is not in the solution

y > -1/2x + 5

y ≤ 3x - 2

a) (5,3) b) (4,3)

c) (3,4) d) (4,4)