Engineering, 20.06.2020 03:57 mncampbell01
Sea B = 5.00 m a 60.0°. Sea C que tiene la misma magnitud que A y un ángulo de dirección mayor que el de A en 25.0°. Sea A ⦁ B = 30.0 m2 y B ⦁ C = 35.0 m2 . Encuentre A.
Answers: 1
, 
y 
, 
y 
son las normas o magnitudes respectivas de los vectores A, B y C, mientras que 
, 
y 
son las direcciones respectivas de aquellos vectores, medidas en grados sexagesimales. 
, 
, 
, 
, 
y 
. Entonces, las ecuaciones quedan simplificadas como siguen:
![35\,m^{2} = 5\|\vec A \| \cdot [\cos 60^{\circ}\cdot \cos (\theta_{A}+25^{\circ}) + \sin 60^{\circ}\cdot \sin (\theta_{A}+25^{\circ})]](/tpl/images/0690/5741/a3792.png)
![35\,m^{2} = \| \vec A \| \cdot [2.5\cdot \cos (\theta_{A}+25^{\circ})+4.330\cdot \sin (\theta_{A}+25^{\circ}})]](/tpl/images/0690/5741/6a069.png)
![35\,m^{2} = \| \vec A \| \cdot [2.5\cdot (0.906\cdot \cos \theta_{A} - 0.423 \cdot \sin \theta_{A})+4.330\cdot (0.906\cdot \sin \theta_{A} + 0.423 \cdot \cos \theta_{A})]](/tpl/images/0690/5741/f8c99.png)
y se desarrolla y simplifica la ecuación resultante: 
y 
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Sea B = 5.00 m a 60.0°. Sea C que tiene la misma magnitud que A y un ángulo de dirección mayor que e...
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