1. The water-gas-shift reaction, CO(g) + H2O(g)  CO2(g) + H2(g) is carried out with the reactants consists of 2 mol of H2O vapor and 1 mol of CO. The temperature is 1,100 K and the pressure is 1 bar. 1). Find out the reaction constant K from the Figure13.2 on the textbook based on the condition given. (5 points) 2). Calculate the fraction of steam reacted. Assume the mixture behaves as an ideal gas. (10 points)

Answer (a) K=1

            (b) 1/3  fraction of steam reacted

Explanation:

CO  + H20 → CO2 + H2

t=0   (1/v)   (2/v)

t= teq   (1-a/v)   (2-a/v)   (a/v)  (a/v)

k= (a/v)²/ (1-a/v)(2-a/v)

1 = a²/(1-a)(2-a)

2-a - 2a + a²= a²

2 = 3a

a = 2/3

Moles of H2O reacted ; a=2/3

Fraction of H2O reacted ; 2/3

                                             2                  = 1/3

1/3 fraction of H20 reacted

this is true

explanation:

i looked it up

answer:

the formula for amps is watts divided by volts. to use the chart, cover up the a with your finger and use the remaining chart calculation of w divided by v. using our sample panel data, 60 watts divided by 12 volts equals 5 amps.

explanation: