Engineering, 06.05.2020 08:33 dreannaevans2

A paint company produces glow in the dark paint with an advertised glow time of 15 min. A painter is interested in finding out if the product behaves worse than advertised. She sets up her hypothesis statements as H0 : µ ≤ 15 and Ha : µ > 15, then calculates a test statistic of z = −2.30. What would be the conclusions of her hypothesis test at significance levels of α = 0.05, α = 0.01, and α = 0.001?

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Answer from: Korey5672

p_v = P(z

Now we can decide based on the significance level $\alpha$ . If p_v we reject the null hypothesis and in other case we FAIL to reject the null hypothesis.

$\alpha=0.05$ we see that $p_v< \alpha$ so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 15

$\alpha=0.01$ we see that $p_v \alpha$ so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

$\alpha=0.001$ we see that $p_v \alpha$ so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

Explanation:

For this case they conduct the following system of hypothesis for the ture mean of interest:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu 15$

The statistic for this hypothesis is:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And on this case the value is given z = -2.30

For this case in order to take a decision based on the significance level we need to calculate the p value first.

Since we have a lower tailed test the p value would be:

p_v = P(z

Now we can decide based on the significance level $\alpha$ . If p_v we reject the null hypothesis and in other case we FAIL to reject the null hypothesis.

$\alpha=0.05$ we see that $p_v< \alpha$ so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 15

$\alpha=0.01$ we see that $p_v \alpha$ so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

$\alpha=0.001$ we see that $p_v \alpha$ so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

Answer from: Quest

unlike the threaded fasteners which are used to clamp the machine members, power screws are used to transmit power. common applications of power screws are: screw jacks: to lift weight. lead screw of lathe: for axial movement of tool and its precise positioning.

Answer from: Quest

answer:

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explanation:

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A paint company produces glow in the dark paint with an advertised glow time of 15 min. A painter is...