int n2 = r - q; // size of right array
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Engineering, 02.03.2020 22:54 yokis2710
Int n1 = q - p + 1; // size of left array
int n2 = r - q; // size of right array
int L[] = new int[n1 + 1];// left array
int R[] = new int[n2 + 1]; //right array
for (int i = 0; i < n1; i++) // going through the first half
{
L[i] = a[p + i];
}
for (int j = 0; j < n2; j++) // going through the second half
{
R[j] = a[q + j + 1];
}
L[n1] = Integer. MAX_VALUE; //sentinel value
R[n2] = Integer. MAX_VALUE;
int i = 0;
int j = 0;
int k = p;
while(i
{
count++;
if (L[i] <= R[j])
{
a[k] = L[i];
i = i + 1;
}
else
{
a[k] = R[j];
j = j + 1;
}
k++;
}
while (i < n1)
{
a[k] = L[i];
i++;
k++;
}
while (j < n2)
{
a[k] = R[j];
j++;
k++;
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Answers: 1
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Int n1 = q - p + 1; // size of left array
int n2 = r - q; // size of right array
int n2 = r - q; // size of right array
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