Write (and test using DS5) an assembly language program in ARMv8 to find the sum, the largest and the smallest of n non-zero positive integers. Declare data sections to store the n positive values as an array v and a variable to store n. Create a loop to go through the array for finding the sum of the elements of the array, the largest and the smallest numbers. Store sum in register X8, largest and smallest values in X9, X10 respectively.

import math

x=int(input("enter a number: "))

print (math.sqrt(math.fabs(

answer:

you shouldn't gave have you all your points.

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)

deez>?

Explanation: