A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces is negligible, determine the normal force between A and the ground when it is at the bottom of the hill.

Explanation:

We firstly determine the impulse momentum of ball B in tangential direction.

Then we simplify the equation for impulse momentum for ball A and ball B.

Now the equation for coefficient of restitution is determined to solve above equation with 2 equations 2 unknowns.

Hence,

Now we apply Conservation of Energy Principle.

Finally, we apply Newton's 2nd Law.

answer:

constructing a building's framework requires a solid foundation

explanation:

answer:

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