sub $s0, $s0, $s1
sub $s0, $s0, $s3
add $s0, $s0, $s1

b) addi $t0, $s6, 4
add $t1, $s6, $0
sw $t1, 0($t0)
lw $t0, 0($t0)
add $s0, $t1, $t0

For the MIPS assembly above, assume that the registers $s0, $s1, $s2, and $s3 contain the values 0x0000000a, 0x00000014, 0x0000001e, and 0x00000028, respectively. Also, assume that register $s6 contains the value 0x00000100, and that memory contains the following values:

Address Value
0x00000100 0x00000064
0x00000104 0x000000c8
0x00000108 0x0000012c

Find the value of $s0 at the end of the assembly code.

Acommercial grade cubical freezer, 4 m on a side, has a composite wall consisting of an exterior sheet of 5.0-mm thick plain carbon steel (kst= 60.5 w/m k), an intermediate layer of 100-mm thick polyurethane insulation (kins 0.02 w/m k), and an inner sheet of 5.0- mm thick aluminium alloy (kal polyurethane insulation and both metallic sheets are each characterized by a thermal contact resistance of r 2.5 x 104 m2 k/w. (a) what is the steady-state cooling load that must be maintained by the refrigerator under conditions for which the outer and inner surface temperatures are 25°c and -5°c, respectively? (b) for power saving purpose, which wall material should be increased/reduced in. thickness in order to reduce 50% of the cooling load found in part (a)? redesign the thickness of the proposed material. 177 w/m-k). adhesive interfaces between the q=575.93 w