Under which of the following conditions is the magnitude of the average velocity of a particle moving in one dimension smaller than the average speed over some time interval? a. a particle moves in the +x direction and then reverses the direction of its motion. b. a particle moves in the +x direction without reversing. c. there are no conditions for which this is true. d. a particle moves in the -x direction without reversing.

The given condition in the question is possible only on condition if a particle moves in the +x direction and then reverses the direction of its motion.

The average speed of particle would:

and the average speed of particle would be:

Therefore, In the given condition that says that average velocity to be less than the average speed would be:

Thus, the correct answer would be if - a particle moves in the +x direction and then reverses the direction of its motion.

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A.

Explanation:

For example,

If you start from 0 and move 5 units in the positive x axis and reverse to return to 2 units from 0, your displacement will be 2 units but distance covered will be 8 units.

Average velocity = Displacement / time

= 2 / time

Average speed = distance / time

= 8 / time

Here, time will be the same, so you can see that magnitude of the average velocity of a particle moving in one dimension smaller than the average speed over some time interval.

import math

x=int(input("enter a number: "))

print (math.sqrt(math.fabs(

yes indeed

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