Write your own implementation of polyval function and name it my_polyval
here is a simple example showiing how polyval function works -

evaluate the polynomial p(x)=3x²+2x+1 at the points 5,7,9 the polynomial coefficients can be represented by the vector [3 2 1].

p = [3 2 1];
x = [5 7 9];
y = polyval(p, x)
y = 1×3
86 162 262
my_polyval needs to be generic. you do not have to use varargin for implementing this, as the function always has two input arguments p and x which are vectors
function:
function y = my_polyval(p, x)
code to call function:
x = [5,7,9];
p1 = [3,2,1];
y1 = my_polyval(p1,x)
p2 = [4,3,2,1];
y2 = my_polyval(p2,x)

The force on a cutting tool are 2600n vertically downward and 2100 horizontal. determine the resultant force acting on the tool and the angle at which it acts.

The temperature of air decreases as it is compressed by an adiabatic compressor. a)- true b)- false

Acommercial grade cubical freezer, 4 m on a side, has a composite wall consisting of an exterior sheet of 5.0-mm thick plain carbon steel (kst= 60.5 w/m k), an intermediate layer of 100-mm thick polyurethane insulation (kins 0.02 w/m k), and an inner sheet of 5.0- mm thick aluminium alloy (kal polyurethane insulation and both metallic sheets are each characterized by a thermal contact resistance of r 2.5 x 104 m2 k/w. (a) what is the steady-state cooling load that must be maintained by the refrigerator under conditions for which the outer and inner surface temperatures are 25°c and -5°c, respectively? (b) for power saving purpose, which wall material should be increased/reduced in. thickness in order to reduce 50% of the cooling load found in part (a)? redesign the thickness of the proposed material. 177 w/m-k). adhesive interfaces between the q=575.93 w