This program currently fails to compile because the parameters cannot be automatically converted to double in the statement triplesum = item1 + item2 + item3; . because thetype is bound to the class number, the number class' doublevalue() method can be called to get the value of the parameters as a double value. modify tripleavg() method to use the doublevalue() method to convert each of the parameters to a double value before adding them.
public class itemminimum {
public static
double tripleavg(thetype item1, thetype item2, thetype item3) {
double triplesum = 0.0;
triplesum = item1 + item2 + item3;
return triplesum / 3.0;
}
public static void main(string[] args) {
integer intval1 = 55;
integer intval2 = 99;
integer intval3 = 66;
double doubleval1 = 14.5;
double doubleval2 = 12.3;
double doubleval3 = 1.75;
// try tripleavg method with integers
system. out. println("items: " + intval1 + " " + intval2 + " " + intval3);
system. out. println("avg: " + tripleavg(intval1, intval2, intval3) + "\n");
// try tripleavg method with doubles
system. out. println("items: " + doubleval1 + " " + doubleval2 + " " + doubleval3);
system. out. println("avg: " + tripleavg(doubleval1, doubleval2, doubleval3) + "\n");
return;
}
}