Water vapor at 5 bar, 320⁰ c enters a turbine operating at steady state with a volumetric flow rate of 0.65 m3 /s and expands adiabatically to an exit state of 1 bar, 160⁰ c. kinetic and potential energy effects are negligible. determine for the turbine
(a) the power developed, in kw
(b) the rate of entropy production, in kw/k
(c) the isentropic turbine efficiency.

Our values are given by,

From steam tables A5 we can calculate the values for State 1, that is,

Here is easily to find the flow mass rate, through

We apply a similar process to State 2, then

With this values we can now calculate the Power, which is given by,

The total rate in entropy, that is

To find the efficiency we know that in a isentropic state, the entropy then

Replacing to find

Then the efficiency is given by,

answer:

explanation:

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