Aspring-mass-spring system is hanging within a wall. one side of mass is having two springs in parallel of 1000 n/m and 3000 n/m. the other side of the mass is having one spring of 4000 n/m. determine the equivalent stiffness.

Explanation:

Given data:

Equivalent of

As we can see from figure  both are parallel to each other therefore equivalent stiffness K is given as

K = 4000 + 4000

K = 8000 n/M

The equivalent stiffness is 8000 N/m

Solution:

As per the question:

Refer to fig 1.

Two springs are connected in parallel on one side with spring constants:

K = 1000 N/m

K' = 3000 N/m

On the other side of the mass, one spring is attached with spring constant:

K" = 4000 N/m

The equivalent of the two spring is given by:

Now, the system is reduced to a two spring system with one spring attached to each side.

Refer to fig 2.

Both the springs are in parallel.

The equivalent stiffness is now given as the sum of the two springs as:

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: