Asingle-degree-of-freedom mass-spring-damper system is observed during its free vibration and the displacement amplitude decays by 9 db from its initial value after 12 cycles. the mass of the system is 7 kg and the spring stiffness is 3,000 n/m. calculate the logarithmic decrement

Logarithmic decrement is equal to 0.182

Explanation:

given,

amplitude decay = 9 dB          

number of cycles = 12 cycles        

mass of the system = 7 kg        

spring stiffness = 3000 N/m            

logarithmic decrement = ?                  

now,                                                      

logarithmic decreament =

                                        =

                                        =ln (1.2)

                                        = 0.182

Hence, Logarithmic decrement is equal to 0.182

answer:

yes that is right have a good day