A7-cm diameter horizontal pipe connected to the side of a tank at 4 m below the water surface in the tank discharges water to the atmosphere. a pump located in the pipe can add head to the flow by the relation, hp (m) = 8 - 200 q^2 (q in m^3/s) if the losses in the system amounts to 5 m, determine the outflow velocity of the pipe.

47.10 m/s

Explanation:

Diameter of the horizontal pipe, d = 7 cm = 0.07 m

Area of the horizontal pipe, A =

or

A =   = 0.00384 m²

Head between the water surface and the pipe level, z = 4 m

Head added by the pump, hp = 8 - 200Q²

where, Q is the discharge

losses, hL = 5 m

now,

applying the Bernoulli's theorem between the water surface and the pipe outlet,

we have

where,

P₁ = pressure at the water surface = 0 (as atmospheric pressure only)

V₁ = Velocity at the free surface = 0

ρ is the density of the water

P₂ = pressure at the outlet = 0 (as atmospheric pressure only)

V₂ = Velocity at the outlet

on substituting the values, we get

or

or

also,

Q = A × V₂

thus,

or

V₂ = 47.10 m/s

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

answer:

ask me the quest

explanation: