If 100 j of heat is added to a system so that the final temperature of the system is 400 k, what is the change in entropy of the system? a)- 0.25 j/k b)- 2.5 j/k c)- 1 j/k d)- 4 j/k

0.25 J/K

Explanation:

Given data in given question

heat (Q) = 100 J

temperature (T) = 400 K

to find out

the change in entropy of the given system

Solution

we use the entropy change equation here i.e  

ΔS = ΔQ / T           a

Now we put the value of heat (Q) and Temperature (T) in equation a

ΔS is the entropy change, Q is heat and T is the temperature,  

so that

ΔS = 100/400 J/K

ΔS = 0.25 J/K

b. check your rearview mirror

explanation:

answer:

no man

explanation:

no i dont want it