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Corey is an architect. what software does he most likely use to design houses? graphic software scheduling software cad software a gps

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Computers and Technology, 22.06.2019 03:30, samone26
Some of your friends have gotten into the burgeoning field of time-series data mining, in which one looks for patterns in sequences of events that occur over time. purchases at stock exchanges--what’s being bought-- are one source of data with a natural ordering in time. given a long sequence s of such events, your friends want an efficient way to detect certain "patterns" in them--for example, they may want to know if the four events buy yahoo, buy ebay, buy yahoo, buy oracle occur in this sequence s, in order but not necessarily consecutively. they begin with a collection of possible events (e. g., the possible’ transactions) and a sequence s of n of these events. a given event may occur multiple times in s (e. g., yahoo stock may be bought many times in a single sequence s). we will say that a sequence s’ is a subsequence of s if there is a way to delete certain of the events from s so that the remaining events, in order, are equal to the sequence s’. so, for example, the sequence of four events above is a subsequence of the sequence buy amazon, buy yahoo, buy ebay, buy yahoo, buy yahoo, buy oracle their goal is to be able to dream up short sequences and quickly detect whether they are subsequences of s. so this is the problem they pose to you: give an algorithm that takes two sequences of even~s--s’ of length m and s of length n, each possibly containing an event more than once--and decides in time o(m n) whether s’ is a subsequence of s
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Computers and Technology, 23.06.2019 16:00, AM28
Does read theory have answers keys ?
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Computers and Technology, 24.06.2019 17:40, xinkyx616
Pseudocode pld #6, pg. 117 start// declarations// number numbertoguess// number myguess; numbertoguess = 92// while myguess ! = numbertoguess// output " guess an integer number between 1 and 100"// input myguess// if (myguess == numbertoguess)// output "you guessed the correct number"// else// output "the number you guessed was incorrect. try again! "// end if// end while// output " for playing the guessing game. have a great day! "// stop
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Computers and Technology, 24.06.2019 21:30, keelynnbarrier
Computer security/cybersecurity1) each of the following code fragments contains a number of security vulnerabilities. for each fragment, identify these security vulnerabilities and, for each vulnerability, discuss at least one way that it could be improved. note that in your discussion of how each vulnerability could be improved, you do not need to re-write a new version of the program in c; simply discuss your solution, either in pseudocode or in 1-2 sentences. a) /* file descriptor leak */#include #include int main(int argc, char *argv[]){ char *filepath = argv[0]; char *shellpath = argv[1]; file *passwords; passwords = fopen(filepath, "r"); /* read the password and do something with it */ /* . . */ /* fork and execute alternative shell */ execl(shellpath, "shell", null); }b)#include /* assume the following function is written for an electronic storefront. the user will enter the id of the item to be ordered, as well as the quantity of units that they would like to purchase. the program will then lookup the price for the price for the item using a predefined function, and return the total cost of the order.*/int gettotalcost(){ char itemid[9]; int price, unitsordered, cost; printf(" enter the 9-digit id of the item to be ordered: "); scanf("%s", & itemid); /* lookup the price according to the itemid */ price = getpricebyid(itemid); printf(" enter the quantity of units to be ordered: "); scanf("%d", & unitsordered); cost = price * unitsordered; return cost; }c)#include /* the following function is intended to return a user's full name by concatenating the user's first and last name into a single string and then returning that string. */char *getfullname(char *firstname, char *lastname, int max_len){ char fullname[max_len]; strcpy(fullname, firstname); strcat(fullname, " "); strcat(fullname, lastname); return fullname; }d)#include /* the following code snippet runs through the list of cli arguments entered and displays them to the console. */int main(int argc, char *argv[]){ int i; printf("you've entered the following arguments: "); for(i = 0; i < argc; i++){ print(argv[i]); printf("\n"); } /* */}
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