Ask the user to enter a number between 10 to 20. If they enter a value under 10, display the message "Too low" and ask them to try again. If they enter a value above 20, display the message "Too high" and ask them to try again. Keep repeating this until they enter a value that is between 10 to 20 and the Answer 12 – Find the missing information [4]

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput. find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }