How is integrating approach in done in teaching

A.) generate scaffolding to create database for your application. develop all the entities identified in assignment #2. add any additional that may be identified later. b.) add data validation rules to the models that are appropriate for your application and data. c.) create links for each scaffold in the header section. part 2: application updates [30 points] a.) add two additional views to the "home" controller you created in assignment #1. b.) the two views should be named as “privacy" and "". c.) link the two newly created views in the footer section. hint: you would need to modify the “home" controller definition and create “privacy. html. erb" and “.html. erb" files in appropriate locations.

Consider a byte-addressable computer with 16mb of main memory, a cache capable of storing a total of 64kb of data and block size of 32 bytes. (a) how many bits in the memory address? (b) how many blocks are in the cache? (c) specify the format of the memory address, including names and sizes, when the cache is: 1. direct-mapped 2. 4-way set associative 3. fully associative

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }