Write a program using a dictionary that reads in a single positive digit number [0 - 9] from the user at the keyboard. Your program will then be able to look up the digit key in the dictionary and print the digit value spelled out. If the user types in a number that is either more than one digit, negative, or a non int value, re-prompt the user for valid input. First, before demonstrating your test cases, print out a display copy of the key:value pairs in your dictionary in sorted order. Deliverable: yournameLab4.py Your source code solution and a copy of the run pasted into your source submission file. Be sure to comment out your run so that your .py file will still run in the grader test bed. Validate user input is a single positive digit [0 - 9].

The program in Python is as follows:

dict = {0:"Zero",1:"One",2:"Two",3:"Three",4:"Four",5:"Five",6:"Six",7:"Seven",8:"Eight",9:"Nine"}

num = input("Number: ")

while(num.isdigit() == False or int(num)<0 or int(num)>9):

   num = input("Number: ")

print(dict)    

print(dict[int(num)])

Explanation:

#This initializes the dictionary

dict = {0:"Zero",1:"One",2:"Two",3:"Three",4:"Four",5:"Five",6:"Six",7:"Seven",8:"Eight",9:"Nine"}

#This gets input from the user

num = input("Number: ")

#This loop is repeated until the user enters a valid input

while(num.isdigit() == False or int(num)<0 or int(num)>9):

   num = input("Number: ")

#This prints the dictionary

print(dict)    

#This prints the value of the key

print(dict[int(num)])

See attachment for sample run

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.

solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.