ASSEMBLY LANGUAGE Using a loop and indexed addressing, write code that rotates the members of a 32-bit integer array forward one position. The value at the end of the array must wrap around to the ?rst position. For example, the array [10,20,30,40] would be transformed into [40,10,20,30].
This is what I got but I need to display the array before and after the rotation something like Array before Rotation: x x x x , Array after rotation: x x x x and also need to input the 4 numbers with the keyboard
.386
.model flat, stdcall
.stack 4096
ExitProcess PROTO, dwExitCode:DWORD
.data
array DWORD 10,20,30,40
arrayType DWORD TYPE array
newArray DWORD LENGTHOF array DUP(?)
lastElement DWORD ?
.code
main PROC
;Get first element address in ESI
MOV ESI, OFFSET array
;Get address of next element in EDI
MOV EDI, OFFSET newArray
ADD EDI, TYPE newArray
;set loop count into ecx
mov ECX, LENGTHOF array
L2:
MOV EAX, [ESI]
MOV [EDI], EAX
ADD ESI, TYPE array
ADD EDI, TYPE array
LOOP L2
;set last element from array in newArray first position
MOV EDI, OFFSET newArray
MOV EAX, [ESI]
MOV [EDI], EAX
INVOKE ExitProcess,0
main ENDP
END main

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