Consider the following program in which the statements are in the incorrect order. Rearrange the statements in the following order so that the program prompts the user to input: 1. The height of the base of a cylinder
2. The radius of the base of a cylinder
The program then outputs (in order):
1. The volume of the cylinder.
2. The surface area of the cylinder
Format the output to two decimal places. #include #include int main() double height; cout << "Volume of the cylinder = " << PI * pow(radius, 2.0) * height << endl; cout << "Enter the height of the cylinder: cin >> radius; cout << endl; return 0; double radius; cout << "Surface area: << 2 * PI * radius * height + 2 * PI * pow(radius, << endl; cout « fixed << showpoint << setprecision(2); cout << "Enter the radius of the base of the cylin cin >> height; cout << endl; #include const double PI = 3.14159; using namespace std;

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Public static int mystery(int a[], int x) {     int c = 0;     for(int i = 0; i < a.length; i++) {        if (a[i] == x) c++;     } return c; }the method counts how many times an integer shows up in an integer array.the c variable is declared in the method to keep track of how many times the certain value has shown up.the for-loop loops through the entire array.the line    if (a[i] == x) c++;   checks if each element of the array is equal to the inputted integer to check. for each number in the array that is equal to the inputted integer x, the c variable will be incremented by 1. otherwise it will do nothing.then c is returned at the end of the loop.for example, if we have, in the main method with the mystery method coded in the class:     int arraytest[] = {2, 23, 23, 23, 3};     int testme = 23;     int count = mystery(arraytest, testme);     system.out.println(count); then the print out will be    3 because there are three 23s in that array.