Consider a computer system with level-1 cache (CL1) and level-2 cache (CL2); where, CL1 access time is 3 cycles, CL2 access time is 14 cycles, and the main memory access time is 130 cycles. For 1000 data requests, there are 100 CL1 misses and 20 CL2 misses. Calculate the speedup (round to two decimal places) due to CL2. [Hints: Calculate EAT1, calculate EAT2, and then calculate Speedup = EAT1/EAT2.)