JAVA Write a method that takes an ArrayList of Strings, and an int numRepeats and returns a new ArrayList with the original ArrayList repeated numRepeats times.

For example if we had an ArrayList list with the values ["a", "b", "c"]:

repeatArrayList(list, 3)

Should return a new ArrayList with the elements:

["a", "b", "c", "a", "b", "c", "a", "b", "c"]

public ArrayList repeatArrayList(ArrayList list, int numRepeats)

{

}

In this lab, you complete a python program that calculates an employee's annual bonus. input is an employee's first name, last name, salary, and numeric performance rating. if the rating is 1, 2, or 3, the bonus rate used is .25, .15, or .1 respectively. if the rating is 4 or higher, the rate is 0. the employee bonus is calculated by multiplying the bonus rate by the annual salary.

What are the different parts of computer

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk, thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\