Write a method for the Runner class that will take in a LinkedList, split into two linked lists, and assign their values to firstItemList and listRemainder. Assign firstItemList to be a new LinkedList that just contains the first value. Assign listRemainder to be a new linkedList that contains everything EXCEPT the remainder. More clearly, if you are given a linked list that looks like: 1 --> 2 --> 3 --> 4 Then assign firstItemList to 1 --> null and listRemainder to `2 --> 3 --> 4`` Please note this will be the only question that deals with a Runner Class instead of the LinkedList class directly. public void split(LinkedList wholeList) {
}// end split
Solve in JAVA please using LinkedList methods and Node methods only if necessary

The following function returns a string of length n whose characters are all 'x'. give the order of growth (as a function of n) of the running time. recall that concatenating two strings in java takes time proportional to the sum of their lengths. public static string f(int n) { if (n == 0) return ""; if (n == 1) return "x"; return f(n/2) + f(n - n/2); } options: a) constant b) logarithmic c) linear d) linearithmic e)quadratic f)cubic g) exponential

What is a scenario where records stored in a computer frequently need to be checked

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }