The code below is repetitious. What is the output of this program? num = 3
num = num + 1
num = num + 1
num = num + 1
print(num)
Output:

When you reach a yield sign, yield to cross traffic and before you enter the intersection. a. flash your headlights b. wait for a signal c. wait five seconds d. wait for a safe gap

If your accelerator suddenly gets stuck what should you do

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i. e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }