This is the question write another function that, given the day that the month starts on and the number of days in that given month, returns the number of days that Inky, Blinky, Pinky and Clyde will get to play pinball in that month. Your function should return a tuple of integers with the respective signature ordering (Inky, Blinky, Pinky, Clyde).

The function provided will increment the day of the week to the next correct day. Use it wisely! def incDay(day) : if (day == "Sunday") : return "Monday" elif (day == "Monday") : return "Tuesday" elif (day == "Tuesday") : return "Wednesday" elif (day == "Wednesday") : return "Thursday" elif (day == "Thursday") : return "Friday" elif (day == "Friday") : return "Saturday" elif (day == "Saturday") : return "Sunday"

This is what I have done so far:

def pinball(day_week, day_month):
if day_month % 4 == 0:
return "Pinky"
else:
if day_week[0] == "T":
return "Inky"
elif day_week[0] == "S":
return "Blinky"
else:
return "Clyde"

def incDay(day) :
if (day == "Sunday") :
return "Monday"
elif (day == "Monday") :
return "Tuesday"
elif (day == "Tuesday") :
return "Wednesday"
elif (day == "Wednesday") :
return "Thursday"
elif (day == "Thursday") :
return "Friday"
elif (day == "Friday") :
return "Saturday"
elif (day == "Saturday") :
return "Sunday"

#Here I don't know what to do#

#these are the test cases#
print("#1", pinball("Sunday",31) == (7,8,7,9))
print("#2", pinball("Wednesday",30) == (7,6,7,10))
print("#3", pinball("Wednesday",0) == (0,0,0,0))

Thats all
Plz help