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Computers and Technology, 23.06.2019 07:50, madim1275
Most shops require the technician to enter a starting and ending time on the repair order to track the actual time the vehicle was in the shop and closed out by the office. this time is referred to as _ time ? a. comeback b. ro c. cycle d. lead
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Computers and Technology, 23.06.2019 15:30, jasssp
Write a program in plp assembly that counts up by one starting from zero (or one) inside a loop and writes this value to the leds every time the value is increased. the memory address of the leds is 0xf0200000. the table below shows the meaning and an example usage of the instructions covered in the video, plp instructions for project 1. instruction example usage meaning load immediate li $t0, 8 register $t0 is set to the value, 8. store word sw $t2, 0($t1) the value in register $t1 is used as the memory address. the value in register $t2 is copied into this memory address. add addiu $t4, $t3, 29 register $t4 is assigned the sum of 29 and the value in register $t3. jump j your_label_name the program jumps to the line following the label, "your_label_name: ". label your label name: defines a label called "your_label_name: " that can be jumped to
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Computers and Technology, 23.06.2019 15:30, yanicas
Hey so i was just trying out some game hacks so i took a paste from online and built it in my visual studio and then suddenly my computer was working or clicking on stuff on its own am i hacked?
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Computers and Technology, 23.06.2019 17:30, Annlee23
When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?
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