Using direct mapping, consider a 16-bit memory addresses, and a cache with 64 blocks, where each block is 8 bytes. What is the size of offset, block, and tag

Tag          Block             Offset

 7               6                   3

Explanation:

Using direct mapping hashing:

Memory address size = 16 bits

Number of cache blocks = 64

Size of each block = 8 bytes

Thus;

Offest field = size of each block = 2^{3} = 3 bits

Number of blocks = 64 = 2

Thus, the index field is = 2^{6} = 6 bits of block

Tag filed is of size = 16 - (3+6) = 7 bits of tag

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.