D. The sum of all odd digits of n. (For example, if n is 32677, the sum would be 3 + 7 + 7 = 17.)

The code is in Java.

It calculates the sum of the odd digit of the number using a while loop and if-else structure.

We extract the last digit of the number, check if it is odd, add it to the sum if it is, then move to the next digit.

Comments are used to explain each line of code.

The output is added as an image.

//Main.java

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 //Scanner object to be able to get input from the user

 Scanner input = new Scanner(System.in);

 //declaring the variables

               int number, digit, sum = 0;

              //getting the number

              number = input.nextInt();

       //while loop that iterates while number is greater than 0

       while(number > 0){

           //get the last digit of the number

           digit = number % 10;

           //check if it is odd. If it is, add the digit to the sum

           if(digit % 2 == 1)

               sum += digit;

           //divide the number by 10 to move to the next digit    

           number /= 10;

       }

       //print the sum

       System.out.println(sum);

}

}

You may check a similar question at:

link

In python:

n = input("What is your number: ")

total = 0

i = 0

while i < len(n):

   if int(n[i]) % 2 != 0:

       total += int(n[i])

   i += 1

print(total)

I hope this helps!

(because i need 20 chars)