Write a single 16-bit LC-3 instruction (in binary) that sets the condition code bits (N, Z, P) according to the value in R0, but does not change any register values. For example, if the current value in R0 is negative, then the N bit should be set after your instruction is executed. But the value in R0 (or any other register) must be unchanged.

Explanation:

To write a single 16-bit LC-3 instruction (in binary) that sets the condition code bits (N, Z, P) according to the value in R0, but does not change any register values, we need to:    Add R0, R0, #0

This implies that the above expression adds value 0 in register 0 which does not make changes to the contents of register 0 but sets the condition code bits (N,Z,P) according to the value in R0.

answer(igmp);