A circuit contains a 12V power supply and two 100ohm resistors that are connected in series. What total current value would you expect to measure in this circuit

total current =0.06A

Explanation:

The total resistance  of Resistors connected in series  is given as  

Rs = R1 + R2 + R3

Here, we have that two resistors are connected in series

therefore,

Rs = 100 + 100 = 200 Ω

But current according to ohm's law is given as

I= V/R

where I= current in ampere, A

V= Voltage in volts, V and

R= Resistance, in ohms,Ω

therefore,

I= V/Rs

I = 12/ 200 = 0.06 A

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