Write a program that takes in an integer in the range 10 to 100 as input. Your program should countdown from that number to 0, printing the count each of each iteration After ten numbers have been printed to the screen, you should start a newline. The program should stop
looping at 0 and not output that value
I would suggest using a counter to cổunt how many items have been printed out and then after 10 items, print a new line character and
then reset the counter.
important: Your output should use %3d" for exact spacing and a space before and after each number that is output with newlines in order
to test correctly. In C please

The program written in C language is as follows

#include<stdio.h>

int main()

{

//Declare digit

int digit;

//Prompt user for input

printf("Enter any integer: [10 - 100]: ");

scanf("%d", &digit);

//Check if digit is within range 10 to 100

while(digit<10 || digit >100)

{

printf("Enter any integer: [10 - 100]: ");

scanf("%d", &digit);

}

//Initialize counter to 0

int counter = 0;

for(int i=digit;i>0;i--)

{

 printf("%3d", i); //Print individual digit

 counter++;

 if(counter == 10) //Check if printed digit is up to 10

 {

 printf("\n"); //If yes, print a new line

 counter=0; //And reset counter to 0

 }

}

}

Explanation:

int digit; ->This line declares digit as type int

printf("Enter any integer: [10 - 100]: "); -> This line prompts user for input

scanf("%d", &digit);-> The input us saved in digit

while(digit<10 || digit >100) {

printf("Enter any integer: [10 - 100]: ");

scanf("%d", &digit); }

->The above lines checks if input number is between 10 and 100

int counter = 0; -> Declare and set a counter variable to 0

for(int i=digit;i>0;i--){ -> Iterate from user input to 0

printf("%3d", i); -> This line prints individual digits with 3 line spacing

counter++; -> This line increments counter by 1

if(counter == 10){-> This line checks if printed digit is up to 10

printf("\n"); -> If yes, a new line is printed

counter=0;} -> Reset counter to 0

} - > End of iteration

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answer is c. complication