Computers and Technology, 21.06.2020 01:57 wypozworski
Consider a byte-addressable main memory consisting of 4 blocks,
and a cache with 2 blocks, where each block is 4 bytes.
This means Block 0 and 2 of main memory map to Block 0 of cache, and
Blocks 1 and 3 of main memory map to Block 1 of cache.
Using the tag, block, and offset fields, we can see how main memory maps to
cache as follows.
First, we need to determine the address format for mapping. Each block is 4
bytes, so the offset field must contain 2 bits; there are 2 blocks in cache, so the
block field must contain 1 bit; this leaves 1 bit for the tag (as a main memory
address has 4 bits because there are a total of 24
=16 bytes).
Answers: 3
Computers and Technology, 24.06.2019 00:30, sethhdoty
Use the keyword strategy to remember the meaning of the following word. the meaning for the word has been provided. write your keyword and describe the picture you would create in your mind. obfuscate: to make something so confusing that it is difficult to understand.
Answers: 2
Consider a byte-addressable main memory consisting of 4 blocks,
and a cache with 2 blocks, where ea...