Computers and Technology, 07.06.2020 21:57 jacksonhoyt8049
I wrote a rock paper scissors game in python but I cannot get it to play again once the user choices a yes option. The rest of the program works.
Here's what I have:
import random
playAgain = True
choice = input("Enter Rock(R), Paper(P), or Scissors(S): ")
computer = random. randint(1, 3)
if computer == 1:
print("Computer played R.")
elif computer == 2:
print("Computer played P.")
else:
print("Computer played S.")
#Winning conditions
if computer == 1 and choice == "R":
print("Computer played Rock.")
print("Tie")
elif computer == 2 and choice == "P":
print("Computer played Paper.")
print("Tie")
elif computer == 3 and choice == "S":
print("Computer played Scissors.")
print("Tie")
elif computer == 1 and choice == "S":
print("Computer played Rock.")
print("You Lose")
elif computer == 2 and choice == "R":
print("Computer played Paper.")
print("You Lose")
elif computer == 3 and choice == "P":
print("Computer played Scissors.")
print("You Lose")
elif computer == 1 and choice == "P":
print("Computer played Rock.")
print("You Win")
elif computer == 2 and choice == "S":
print("Computer played Paper.")
print("You Win")
elif computer == 3 and choice == "R":
print("Computer played Scissor.")
print("You Win")
#Play again?
choice = input("Play Again? ")
while playAgain == True:
if choice == "y":
playAgain = True
elif choice == "yes":
playAgain = True
if choice == "Yes":
playAgain = True
elif choice == "Y":
playAgain = True
elif choice == "n":
print("Thanks for playing!")
exit()
elif choice == "no":
print("Thanks for playing!")
exit()
elif choice == "N":
print("Thanks for playing!")
exit()
elif choice == "No":
print("Thanks for playing!")
exit()
else:
print("Please input a vaild option.")
choice = input("Play Again? ")
Answers: 2
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I wrote a rock paper scissors game in python but I cannot get it to play again once the user choices...
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