Design a program in python that is able to take a user's input of either "Rock", "Paper", or "Scissors" and based on their input, output to them what their choice will beat in a "rock, paper, scissors" game. Additionally, if the user misspells or enters a wrong input tell them that they have made a mistake.

Here you go:

Explanation:

# import random module  

import random  

# Print multiline instruction  

# performstring concatenation of string  

print("Winning Rules of the Rock paper scissor game as follows: \n"

       +"Rock vs paper->paper wins \n"

       + "Rock vs scissor->Rock wins \n"

       +"paper vs scissor->scissor wins \n")  

while True:  

print("Enter choice \n 1. Rock \n 2. paper \n 3. scissor \n")  

# take the input from user  

choice = int(input("User turn: "))  

# OR is the short-circuit operator  

# if any one of the condition is true  

# then it return True value  

# looping until user enter invalid input  

while choice > 3 or choice < 1:  

 choice = int(input("enter valid input: "))  

# initialize value of choice_name variable  

# corresponding to the choice value  

if choice == 1:  

 choice_name = 'Rock'

elif choice == 2:  

 choice_name = 'paper'

else:  

 choice_name = 'scissor'

# print user choice  

print("user choice is: " + choice_name)  

print("\nNow its computer turn")  

# Computer chooses randomly any number  

# among 1 , 2 and 3. Using randint method  

# of random module  

comp_choice = random.randint(1, 3)  

# looping until comp_choice value  

# is equal to the choice value  

while comp_choice == choice:  

 comp_choice = random.randint(1, 3)  

# initialize value of comp_choice_name  

# variable corresponding to the choice value  

if comp_choice == 1:  

 comp_choice_name = 'Rock'

elif comp_choice == 2:  

 comp_choice_name = 'paper'

else:  

 comp_choice_name = 'scissor'

print("Computer choice is: " + comp_choice_name)  

print(choice_name + " V/s " + comp_choice_name)  

# condition for winning  

if((choice == 1 and comp_choice == 2) or

(choice == 2 and comp_choice ==1 )):  

 print("paper wins => ", end = "")  

 result = "paper"

elif((choice == 1 and comp_choice == 3) or

 (choice == 3 and comp_choice == 1)):  

 print("Rock wins =>", end = "")  

 result = "Rock"

else:  

 print("scissor wins =>", end = "")  

 result = "scissor"

# Printing either user or computer wins  

if result == choice_name:  

 print("<== User wins ==>")  

else:  

 print("<== Computer wins ==>")  

print("Do you want to play again? (Y/N)")  

ans = input()  

# if user input n or N then condition is True  

if ans == 'n' or ans == 'N':  

 break

# after coming out of the while loop  

# we print thanks for playing  

print("\nThanks for playing")  

answer; i believe the correct answer is (a) all trenches must have access/egress;

answerdragging;