Public class Test { public static void main(String[] args) { try { method(); System. out. println("After the method call"); } catch (ArithmeticException ex) { System. out. println("ArithmeticException"); } catch (RuntimeException ex) { System. out. println("RuntimeException"); } catch (Exception e) { System. out. println("Exception"); } } static void method() throws Exception { System. out. println(1 / 0); } }

"ArithmeticException" is the correct answer for the above question.

Explanation:

Missing Information : The above question does not hold that "what is the output of the program".

The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.The method function holds one run time exception which is 1/0 which is an arithmetic exception.It can be handle by the help of an arithmetic class object which is defined in the first catch block.Hence the print function of this catch is executed and prints "ArithmeticException".

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