Computers and Technology, 21.04.2020 19:29 jaejaeJae9534
For the following two transactions and the initial table values as shown complete the missing blanks in the transaction log below:
Part_ID
Desrption
OnHand
OnOrder
57
Assembled Foo
5
0
987
Foo Fastener
12
7
989
Foo Half
7
0
BEGIN TRANSACTION;
UPDATE Part SET OnHand = OnHand + 7, OnOrder = OnOrder – 7 WHERE Part_ID = 987;
COMMIT;
BEGIN TRANSACTION;
UPDATE Part SET OnHand = OnHand - 4 WHERE Part_ID = 987;
UPDATE Part SET OnHand = OnHand - 2 WHERE Part_ID = 989;
UPDATE Part SET OnHand = OnHand + 1 WHERE Part_ID = 57;
COMMIT
TRL_ID
TRX_ID
PREV_PTR
NEXT_PTR
OPERATION
TABLE
ROW ID
ATTRIBUTE
BEFORE VALUE
AFTER VALUE
1787
109
NULL
START
1788
109
1787
UPDATE
PART
987
OnHand
12
1789
109
UPDATE
PART
987
OnOrder
7
1790
109
NULL
COMMIT
1791
110
NULL
START
Answers: 1
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For the following two transactions and the initial table values as shown complete the missing blanks...
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