The accounting department moved its network-attached printer from one side of the office to a more centralized location, making the printer much more accessible to all accounting users. Since the move, the users have not been able to print to the printer. The printer powers on and shows it is ready to accept print jobs. The printer configuration page shows the following output. IP Configuration: DHCPIP Address: 169.254.101.132Subnet Mask:255.255.0.0Default Gateway:You disconnect the patch cable from the keystone jack at the new location and move the printer and cable to reconnect it at the original location. The printer begins printing the jobs that failed to print earlier. What are the most likely reasons for the printer failing to print at the new location?

You are new to microsoft certification and want to start out by getting a certification geared around windows 8. what microsoft certification should you pursue?

Write the html code to make a link out of the text “all about puppies”. it should link to a pdf called “puppies. pdf” inside the “documents” folder. the pdf should open in a new window.

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }