It is assumed that there are at least 40 packets buffered in the queue to be sent out by the sender, the network is stable (i. e., the propagation time between the sender and the server is roughly the same for every data packet and ack if it is not lost), the total transmission delay of 3 data packets are much smaller than RTT, 8-bit sequence numbers are used, window size N = 3, and initial send_base = 15.

Draw a diagram similar to PPT slide 21 titled "GBN in action" of Chapter 3 for the Go-Back-N approach to illustrate the interaction between the sender and the receiver between the moment when pkt15 is sent the first time by the sender and the moment when pkt21 is sent out the first time by the sender. During the interaction, only three abnormal events occur: pkt16 is lost on the way when it is sent to the receiver the FIRST time, the timer for pkt16 expires after ack#15 is received by the sender the SECOND time, and ack17 is lost on the way when it is sent to the sender the FIRST time. Please include all the details as given in PPT slide 21 in your diagram.

What are the values of send_base, nextseqnum, and N in this particular case?

Select the correct answer. sean is a computer programmer. he has programmed an application for toddlers that plays nursery rhymes. however, a logic error has occurred in the program. which problem is a likely consequence of the error? a. the program crashes every time the user wants to play the nursery rhymes. b. the program crosses its buffer boundaries and overwrites an adjacent program. c. the program plays a different nursery rhyme than the one the user intended to play. d. the program shows different structures in its programming language code. e. the program introduces new viruses every time the user plays a nursery rhyme.

How often does colleges update the cost of attendance on their website? . a)every two years b) every four years c) every year d) every semester

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }